assembly - MIPS simple Sum -

i friends,

i'm working on compiler program so, can't understand while i'm passin 3 code address mips assembly, gets error in simple sums those:

addi $t0 , 1 ,1

it accepts :

addi temp , temp , 1

how can sum 2 integers? have store first "1" in temporary?

thanks lot

yes. each instruction has 32-bits encode operation, registers , in case immediate value. immediate value alone consumes 16-bits, there aren't instructions 2 immediates. question why ever need 2 immediate values. if have 2 constants want put code, compute answer , put answer instruction code.