Using pointers to get value from multidimensional array - C -

i trying value "second row" in multidimensional array. have problems that. thought numbers stored sequentialy in memory tab[2][2] stored same tab[4]. seems wrong.

this tried:

int b[2][2] = {{111,222},{333,444}}; int = 0; for(;i < 100; i++)     printf("%d \n", **(b+i)); 

the problem 111 , 333 result. there no 222 or 444 in other 98 results. why?

the problem **(b+i) doesn't think does. evaluates to:

b[i][0] 

as matt mcnabb noted,

**(b+i) 

is equivalent to:

*(*(b+i)+0) 

and since *(b+i) equivalent b[i], expression whole can seen as:

*(b[i]+0) 

and hence:

b[i][0] 

since array has 2 rows, values of i 0 , 1 in bounds of array (that's 111 , 333). rest wildly out of bounds.

what is:

#include <stdio.h>  int main(void) {     int b[2][2] = { { 111, 222 }, { 333, 444 } };     int *base = &b[0][0];      (int = 0; < 4; i++)         printf("%d: %d\n", i, base[i]);     return 0; } 

output:

0: 111 1: 222 2: 333 3: 444