Javascript confirm multiple changes -

i want alert user changes made in 4 fields. script works 1 @ time. if 1 or 4 changes have been made, alerts first 1 , skips others. displayed in 1 confirm box.

<script> function validateform() { var w = document.getelementbyid("item_name"); if (w.value != w.defaultvalue) {   return confirm('update item name. continue?'); }  var x = document.getelementbyid("item_brand");           if (x.value != x.defaultvalue) { return confirm('update item brand. continue?'); }  var y = document.getelementbyid("department_id");            if (!y.options[y.selectedindex].defaultselected) { return confirm('update item department. continue?'); }  var z = document.getelementbyid("vendor_part_num");          if (z.value != z.defaultvalue) { return confirm('update vendor part number. continue?'); }  } </script>     

you don't want ask each field individually, first check them all, ask user, this

<script> function validateform() { var strquestion = ''; var bstchanged = false; var w = document.getelementbyid("item_name"); if (w.value != w.defaultvalue) {   bstchanged = true;   strquestion = strquestion + 'update item name.' + string.fromcharcode(13); }  var x = document.getelementbyid("item_brand");           if (x.value != x.defaultvalue) {   bstchanged = true;   strquestion = strquestion + 'update item brand.' + string.fromcharcode(13); }  var y = document.getelementbyid("department_id");            if (!y.options[y.selectedindex].defaultselected) {   bstchanged = true;   strquestion = strquestion + 'update item deparment.' + string.fromcharcode(13); }  var z = document.getelementbyid("vendor_part_num");          if (z.value != z.defaultvalue) {   bstchanged = true;   strquestion = strquestion + 'update vendor part number.' + string.fromcharcode(13); }  if (bstchanged) {   return confirm(strquestion + ' continue?') }  } </script>